Despite the loss of order in the crystal lattice and the entropy of mixture, system entropy may actually decrease in the solution process with certain electrolytes due to the order imposed on the water molecules that form hydration spheres around the dissolved ions.
In addition to the heat flow (internal energy change, electrostatic potential energy), that plays a roll in determining the difference between the undissolved and dissolved state is the difference in entropy. Despite the entropy of mixture, which might make you think that dissolving an electrolyte in water increases the entropy of the system, the solution process involving an electrolyte in water may actually cause the entropy to decrease, because the water molecules become more ordered as they are constrained in the orderly geometry of hydration spheres. (This difference is an important, advanced sub-theme in the salting-out technique of protein purification.) In other words, a decrease in system entropy may occur despite the entropy of mixture, which would dominate in the solution of an organic solute in an organic solvent, where there is very little constraint to molecular orientation. With a typical nonpolar solute in nonpolar solvent, the entropy definitely increases in the system over the course of the solution process, but when ions are dissolved in water, the system increases in its order.
Let us finish this discussion with the question. Why do such salts dissolve at all? Almost all solution processes are endothermic (We know this because solubility increases with temperature, ie. Le Chatelier's Principle). Furthermore, the solution of our electrolyte in an aqueous solution represents more order. Why then, when you place the salt in water, does it spontaneously dissolve, even if only sparingly? The answer is that our question is off base, a trick of language. When you have a salt ready to dissolve in pure water, you are not looking at a system with equal amounts of Reagents A and Products B. The answer is that your initial state is not the Standard State (quantifying the Standard State is a complicated problem for a nonhomogeneous process like this, i.e. having both solids and liquids). In the initial state of the solution process, you are starting with only Reagents A. Of course the direction the reaction takes toward equilibrium is toward the products, in other words, dissolving, even though a Standard State comparison of the solution process has positive free energy change. The greater this positive free energy change, though, the less soluble the salt will be.
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